Din tr AMC=tr ANB rezulta ca : AB=AC (deci tr ABC este isoscel)  b) AM=AN, deci si AB-AM=AC-AN, adica: BM=CN  a) m(

[latex]igtriangleup AMC equiv igtriangleup ANB \ ([OB] equiv ([OC] \ ---------- \ ([BM]=([CN] \ igtriangleup ABC~isoscel \ ([OM] equiv ([ON] \ ---------- \ igtriangleup AMC equiv igtriangleup ANB Longrightarrow AM=AN \ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~MC=NB \ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~AC=AB \ a)BM=AB-AM \ CN=AC-AN \ AC=AB~si~AM=AN Longrightarrow oxed{BM=CN} \ b)AB=AC Longrightarrow oxed{igtriangleup ABC ~isoscel} \[/latex] [latex]c)OM=MC-OC \ ON=NB-OB \ OB=OC~si~MC=NB Longrightarrow oxed{OM=ON}[/latex]