Afla nr necunoscut in fiecare caz 4+2[2+(6+a):3]-20=0
[936-(40×20-b)]:[20+(63:9+96:12)]=8
[(2086:7-9×8)+a:4]:[(125-4×25):5]=35×4-82
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2016-09-26 06:04:18
4+2[2+(6+a):3]-20=0 4+2[2+(6+a):3]=0+20=20 2[2+(6+a):3]=20-4=16 [2+(6+a):3]=16:2=8 (6+a):3=8-2=6 6+a=6×3=18 a=18-6 a=12 [936-(40×20-b)]:[20+(63:9+96:12)]=8 [936-(800-b)]:[20+(7+8)]=8 [936-(800-b)]:(20+15)=8 [936-(800-b)]:35=8 [936-(800-b)]=8×35=280 800-b=936-280=656 b=656+800 b=1456 [(2086:7-9×8)+a:4]:[(125-4×25):5]=35×4-82 [(298-72)+a:4]:[(125-100):5]=140-82 (226+a:4):(25:5)=58 (226+a:4):5=58 (226+a:4)=58×5=290 a:4=290-226 a:4=64 a=64×4 a=256
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