Matematică
Cosmina200
2015-11-12 01:53:57
a) 3+7×x<52 b) 5×x-23>22 c)6×x-18>72 d)3×x+11<44
Răspunsuri la întrebare
adeliin
2015-11-12 02:46:09

Salut, a) 3+7x < 52 7x < 52-3 7x < 49 x < 49/7 x < 7. x € (-∞;7). b) 5x-23 > 22 5x > 22+23 5x > 45 x > 45/5 x > 9. x € (9;+∞). c) 6x-18 > 72 6x > 72+18 6x > 90 x > 90/6 x > 15 x € (15;+∞). d)3x+11 < 44 3x < 44-11 3x < 33 x < 33/3 x < 11. x € (-∞;11). Succes! :3

teovtm
2015-11-12 02:47:24

a)...   3 + 7x < 52 => 7x<52-3  adica: 7x<49  => x < 49:7=7 ; b)...5x-23>22       => 5x>45     adica: x > 45:5=9 ; c)... 6x - 18 > 72  => 6x > 90   => x > 90:6=15 ; d)... 3x < 44-11   =>  3x < 33   => x < 11 ;

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